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authorGustavo A. R. Silva <[email protected]>2018-08-23 13:51:40 -0500
committerAlexandre Belloni <[email protected]>2018-08-27 23:02:18 +0200
commit725e0e15f84bb30e83fad8fa4b4dd1f335506172 (patch)
treef4242387a71957aded2e03b88eca2f9fb71a0e5c /tools/perf/scripts/python
parent1e6e4e169a8aef8127ff9ffece6290fafe0d92bf (diff)
rtc: sun6i: Use struct_size() in kzalloc()
One of the more common cases of allocation size calculations is finding the size of a structure that has a zero-sized array at the end, along with memory for some number of elements for that array. For example: struct foo { int stuff; void *entry[]; }; instance = kzalloc(sizeof(struct foo) + sizeof(void *) * count, GFP_KERNEL); Instead of leaving these open-coded and prone to type mistakes, we can now use the new struct_size() helper: instance = kzalloc(struct_size(instance, entry, count), GFP_KERNEL); Signed-off-by: Gustavo A. R. Silva <[email protected]> Reviewed-by: Kees Cook <[email protected]> Signed-off-by: Alexandre Belloni <[email protected]>
Diffstat (limited to 'tools/perf/scripts/python')
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